已知A=3x+2y的平方,B=x的平方-2xy减y的平方,绝对值x+1等于3,绝对值y减1=2,求A加B

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2025-12-17 00:00:19
推荐回答(2个)
回答1:

∵|x+1|=3 且 |y-1|=2

∴可以得出x和y的四组解,分别为
(1)x=2, y=3
(2)x=2, y=-1
(3)x=-4, y=3
(4)x=-4, y=-1

A=(3x+2y)^2, B=x^2-2xy-y^2,
A+B = 9x^2+12xy+4y^2+x^2-2xy-y^2
= 10x^2+10xy+3y^2

把以上四组解分别代入,
得:
(1)A+B=127
(2)A+B=23
(3)A+B=67
(4)A+B=203

回答2:

|x+1|=3 且 |y-1|=2

可得(1)x=2, y=3
(2)x=2, y=-1
(3)x=-4, y=3
(4)x=-4, y=-1

A=(3x+2y)^2, B=x^2-2xy-y^2,
A+B = 9x^2+12xy+4y^2+x^2-2xy-y^2
= 10x^2+10xy+3y^2


(1)A+B=127
(2)A+B=23
(3)A+B=67
(4)A+B=203