已知数列an的前n项的和为sn=3n^2+n-1,求通项公式an

2025-12-14 01:17:12
推荐回答(2个)
回答1:

a1=s1 = 3+1-1 = 3
an = sn -sn-1
= 3n² +n-1 - (3(n-1)² +(n-1) -1)
= 3(n+n-1)*1 +1
= 3(2n -1) +1
= 6n -2

n=1时a1 =3
n>=2时 an = 6n -2

回答2:

an=sn-s(n-1)