x十y=6,xy=8,求x的4次方加y的4次方等于多少

2025-12-14 02:15:47
推荐回答(2个)
回答1:

x十y=6
(x十y)^2=36
x^2+y^2+2xy=36
xy=8
x^2+y^2=36-16=20
(x^2+y^2)^2=400
x^4+y^4+2x^2y^2=400, x^2y^2=(xy)^2=8^2=64
x^4+y^4=400-2乘以64
=272

回答2:

:x^4+y^4=(x^2+y^2)^2-2x^2y^2=[(x+y)^2-2xy]^2-2(xy)^2=(36-16)^2-2*64=272