一道高数题在线等

2025-03-18 20:45:43
推荐回答(4个)
回答1:

😜😜

回答2:

回答3:

y = (x^2-1)/(x^2-3x-4) = (x-1)(x+1)/[(x+1)(x-4)]
间断点 x = -1, x = 4
lim(x-1)(x+1)/[(x+1)(x-4)] = lim(x-1)/(x-4) = 2/5,
x = -1 是可去间断点;
lim(x-1)(x+1)/[(x+1)(x-4)] = ∞,
x = 4 是无穷间断点。

回答4: