(x-1)^3+(x-2)^3+(3-2x)^3=(x-1+x-2)[(X-1)^2-(X-1)(X-2)+(X-2)^2]+(3-2x)^3=(2X-3)[(X-1)^2-(X-1)(X-2)+(X-2)^2-(3-2X)^2]=(2X-3)[(X-1)^2-(X-1)(X-2)+(1-X)(3X-5)]=(2X-3)(X-1)[(X-1)-(X-2)-(3X-5)]=(2X-3)(X-1)(6-3X)=-3(2X-3)(X-1)(X-2)
(*^__^*) ,是八(1)班的么?